如图所示突然放大有压管流,放大前细管直径d1= 100mm,放大后粗管直径d2=200mm,若放大后断面平均流速v2=1m/s,则局部水头损失hm为: ...

作者: tihaiku 人气: - 评论: 0
问题 如图所示突然放大有压管流,放大前细管直径d1= 100mm,放大后粗管直径d2=200mm,若放大后断面平均流速v2=1m/s,则局部水头损失hm为: A. 0. 613m B. 0. 556m C. 0. 459m D. 0. 343m
选项
答案 C
解析

相关内容:如图,压管,直径,粗管,断面,流速,局部,水头,损失

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