有一箱形基础,上部结构和基础自重传至基底的压力p = 120kPa,若地基土的天然重度γ= 18kN/m3,地下水位在地表下12m处,当基础埋置在( )深...

作者: rantiku 人气: - 评论: 0
问题 有一箱形基础,上部结构和基础自重传至基底的压力p = 120kPa,若地基土的天然重度γ= 18kN/m3,地下水位在地表下12m处,当基础埋置在( )深度时,基底附加压力正好为零。 A. d =4. 4m B. d=5. 67m C. d=6. 67m D. d=7.67m
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答案 C
解析 基底附加应力计算公式为:p0=p-γ0d,则。将题中条件代入可得: d=120/18 =6. 67m。
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